- Show that
- $\lg(n!)= \Theta(n\lg n)$
- $(\lg n)^{\lg n}=o(e^n)$
- $(\lg n)^2=o(\sqrt{n})$
- Determine whether $5^{\lg n}=o(n^{5/2})$ or $n^{5/2}=o(5^{\lg n})$.
